Two mutually perpendicular linear simple harmonic motions of equal amplitude and frequency are imposed on a particle along x and y axis respectively. The initial phase difference between them is π/2. The resultant path followed by the particle is:
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a
a circle
b
a straight line
c
an ellipse
d
a parabola
answer is A.
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Detailed Solution
Let the component SHM's be x = A cos ωt and y = A cos(ωt - π/2)The equation represents a circle of radius A with its centre at the origin.