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Q.

Two nonconducting infinite plane sheets having charges Q and 2Q are placed parallel to each other as shown in figure. The charge  distribution on the four faces of the two plates is also shown. The electric field intensities at three points 1, 2, and 3 are E1,  E2  and  E3, respectively. Then the magnitudes of E1,  E2  and  E3  are, respectively (surface area of plates)

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a

zero,  Qε0S,zero

b

5Q6ε0S,Q2ε0S,zero

c

5Q6ε0S,Qε0S,Q3ε0S

d

zero,Q2ε0S,zero

answer is B.

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Detailed Solution

Let us take rightward as positive and leftward as negative.These four faces can be considered four thin infinite plane sheets.E→1=12ε0S[2Q3−Q3−Q2−3Q2]=−5Q6ε0SE→2=12ε0S[2Q3+Q3−Q2−3Q2]=−Q2ε0SE→3=12ε0S[2Q3+Q3+Q2−3Q2]=0
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