Two nonconducting infinite plane sheets having charges Q and 2Q are placed parallel to each other as shown in figure. The charge distribution on the four faces of the two plates is also shown. The electric field intensities at three points 1, 2, and 3 are E1, E2 and E3, respectively. Then the magnitudes of E1, E2 and E3 are, respectively (surface area of plates)
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a
zero, Qε0S,zero
b
5Q6ε0S,Q2ε0S,zero
c
5Q6ε0S,Qε0S,Q3ε0S
d
zero,Q2ε0S,zero
answer is B.
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Detailed Solution
Let us take rightward as positive and leftward as negative.These four faces can be considered four thin infinite plane sheets.E→1=12ε0S[2Q3−Q3−Q2−3Q2]=−5Q6ε0SE→2=12ε0S[2Q3+Q3−Q2−3Q2]=−Q2ε0SE→3=12ε0S[2Q3+Q3+Q2−3Q2]=0