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Gauss's law and its applications

Question

Two nonconducting plates A and B of radii 2R and 4R, respectively, are kept at distances x and 2x from the point charge q. A surface cutout of a nonconducting shell C is kept such that its center coincides with the point charge. Each plate and spherical surface carries surface charge density σ.

Difficult
Question

If FA, FB, and FC are the forces on plate A, plate B, and spherical surface C due to charge q, respectively, then

Solution

For A and B we know that

 Flux=ϕ=Eds Force =σEds=σEds=σϕ

As flux due to charge q in each plate is same, so force will be same.
For C we have taken the horizontal component of electric field, but for flux, we do not have to take the component of electric field.
As force due to one plate on another plate is same, hence ϕ due to 1 in another and due to 2 in 1 will be same.
When x and R increased, ϕ in plate due to charge remains same, hence force due to charge on plates does not change.

Question

If ϕ1 is flux through surface of (B) due to electric field of (A) and ϕ2 is the flux through (A) due to electric field of (B), then

Solution

For A and B we know that

 Flu x=ϕ=Eds Force =σEds=σEds=σϕ

As flux due to charge q in each plate is same, so force will be same.
For C we have taken the horizontal component of electric field, but for flux, we do not have to take the component of electric field.
As force due to one plate on another plate is same, hence ϕ due to 1 in another and due to 2 in 1 will be same.
When x and R increased, ϕ in plate due to charge remains same, hence force due to charge on plates does not change.

Question

If distance x and radius R are doubled so that FA becomes FA, FB becomes FB, then the correct option is

Solution

For A and B we know that

 Flu x=ϕ=Eds Force =σEds=σEds=σϕ

As flux due to charge q in each plate is same, so force will be same.
For C we have taken the horizontal component of electric field, but for flux, we do not have to take the component of electric field.
As force due to one plate on another plate is same, hence ϕ due to 1 in another and due to 2 in 1 will be same.
When x and R increased, ϕ in plate due to charge remains same, hence force due to charge on plates does not change.



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Similar Questions

In an insulating medium (dielectric constant = 1) the charge density varies with y co-ordinate as ρ=50ε0y C/m3. The electric field is zero at y = 0 and everywhere else it is along y direction. Find the electric field at y = 4 m (in N/C).


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