Two objects are moving along the same straight line. They cross a point A with an acceleration a and 2 a and velocity 2 u and u at time t=0. The distance moved by the object when one overtakes the other is

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6u2a

2u2a

4u2a

8u2a

answer is A.

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Detailed Solution

At the time of overtaking.s1=s2 . 2ut+12at2 Therefore, 2u t +12at2=ut+12(2a)t2t ⇒t=2ua Therefore, s1=s2=(2u)2ua+12(a)2ua2 =6u2a

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