Two objects of masses m1 and m2 are lying at rest a certain distance apart on the x-axis. A constant force F acts on m2 at time t = 0 as shown in Fig. The velocity of the centre of mass of the system at time t will be (m2 > m1).

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zero

Ftm2

Ftm1+m2

Ftm2−m1

answer is C.

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Detailed Solution

u1=0,u2=0. Acceleration of m2 is a=Fm2∴Velocity of m2 at time t is v2=u2+at=0+Ftm2 or v2=Ftm2.The velocity of the centre of mass isvcm=m1u1+m2v2m1+m2=0+m2×Ftm2m1+m2=Ftm1+m2, which is choice (c)

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