Two objects moving along the same straight line are leaving point A with an acceleration a,2a and velocity 2u, u respectively at time t=0. The distance moved by theobject with respect to point A when one object overtakes the other is
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a
3u2a
b
2u2a
c
4u2a
d
6u2a
answer is D.
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Detailed Solution
Let both will meet at point Bx=2ut+12at2⇒x=ut+12(2a)t2 So 2ut+12at2=ut+at2 ut=12at2⇒t=2ua So x=2u2ua+12a2ua2=6u2a