Two opposite and equal charges 4 × 10–8 coulomb when placed 2 × 10–2 cm away, from a dipole. If this dipole is placed in an external electric field 4 × 108 newton/coulomb, the value of maximum torque and the work done in rotating it through 180o will be
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a
64 × 10–4Nm and 64 × 10–4J
b
32 × 10–4Nm and 32 × 10–4J
c
64 × 10–4Nm and 32 × 10–4J
d
32 × 10–4Nm and 64 × 10–4J
answer is D.
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Detailed Solution
Max . Torque = PE = q × a × E= 4 × 10–8 × 2 × 10–4 × 4 × 108= 32 ×10–4 Nmw = PE(cos0º - cos180º) = 2 PE = 64 × 10–4 J