Two opposite and equal charges 4 × 10–8 coulomb when placed 2 × 10–2 cm away, from a dipole. If this dipole is placed in an external electric field 4 × 108 newton/coulomb, the value of maximum torque and the work done in rotating it through 180o will be

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64 × 10–4Nm and 64 × 10–4J

32 × 10–4Nm and 32 × 10–4J

64 × 10–4Nm and 32 × 10–4J

32 × 10–4Nm and 64 × 10–4J

answer is D.

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Detailed Solution

Max . Torque = PE = q × a × E= 4 × 10–8 × 2 × 10–4 × 4 × 108= 32 ×10–4 Nmw = PE(cos0º - cos180º) = 2 PE = 64 × 10–4 J

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