Questions
Two opposite and equal charges coulomb when placed cm away from a dipole. If this dipole is placed in an external electric field newton / coulomb the value of maximum torque and the work done in rotating it through will be
detailed solution
Correct option is D
Dipole moment p=qd = 4×10−8 ×2×10−4=8×10−12 CmMaximum torque=pEsinθ=pEsin90=8×10−12×4×108=32×10−4 NmWork done in rotating through1800=pE(cosθ1-cosθ2)==pE(cos0-cos180)=2pE=2×32×10−4=64×10−4JTalk to our academic expert!
Similar Questions
A point charge Q is fixed at origin. A dipole of dipole moment
799 666 8865
support@infinitylearn.com
6th Floor, NCC Building, Durgamma Cheruvu Road, Vittal Rao Nagar, HITEC City, Hyderabad, Telangana 500081.
JEE Mock Tests
JEE study guide
JEE Revision Notes
JEE Important Questions
JEE Sample Papers
JEE Previous Year's Papers
NEET previous year’s papers
NEET important questions
NEET sample papers
NEET revision notes
NEET study guide
NEET mock tests