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Two opposite and equal charges 4×10−8 coulomb when placed 2×10−2 cm away from a dipole. If this dipole is placed in an external electric field 4×108 newton / coulomb the value of maximum torque and the work done in rotating it through 1800 will be

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a

64×10−4Nm and 64×10−4J

b

32×10−4Nm and 32×10−4J

c

64×10−4Nm and 32×10−4J

d

32×10−4Nm and 64×10−4J

answer is D.

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Detailed Solution

Dipole moment p=qd = 4×10−8 ×2×10−4=8×10−12 CmMaximum torque=pEsinθ=pEsin90=8×10−12×4×108=32×10−4 NmWork done in rotating through1800=pE(cosθ1-cosθ2)==pE(cos0-cos180)=2pE=2×32×10−4=64×10−4J

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Two opposite and equal charges 4×10−8 coulomb when placed 2×10−2 cm away from a dipole. If this dipole is placed in an external electric field 4×108 newton / coulomb the value of maximum torque and the work done in rotating it through 1800 will be