Two organ pipes both closed at one end, have lengths l and l+Δl . If the velocity of sound in air is ν , then the number of beats per second produced is :
υ4l
υ2l
υ4l2Δl
υ2l2Δl
n1=V4l n2=V4l+Δl
Beats n1− n2=V4l1l−1l+Δl
=V4l1−11+Δll
n1−n2=V4l1−1+Δll−1
=V4l1−1−Δll
=V4lΔll=VΔl4l2
Short cut
n=v4l⇒dn=-v4l2dl