Questions
Two organ pipes both closed at one end, have lengths and . If the velocity of sound in air is , then the number of beats per second produced is :
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Correct option is C
n1=V4l n2=V4l+ΔlBeats n1− n2=V4l1l−1l+Δl=V4l1−11+Δlln1−n2=V4l1−1+Δll−1=V4l1−1−Δll=V4lΔll=VΔl4l2Short cutn=v4l⇒dn=-v4l2dl
Similar Questions
A cylindrical tube, open at both ends has fundamental frequency ‘f’ in air. The tube is dipped vertically in water so that half of it is in water. The fundamental frequency of the air column is now
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