First slide

Projection Under uniform Acceleration

Question

Two paper screens A and B are separated by a distance of 100 m. A bullet pierces A and then B. The hole in B is 10 cm below the hole in A. If the bullet is travelling horizontally at the time of hitting A, then the velocity of the bullet at A is

Easy

A

100 m/s
B

200 m/s
C

600 m/s
D

700 m/s

Solution

See fig.
Here $100 = ut or t = \frac{100}{u}$
Also $(\frac{10}{100}) = \frac{1}{2} \times (9 \cdot 8) \times {(\frac{100}{u})}^{2}$
Solving, we get u = 700 m/s

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