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Two paper screens A and B are separated by 150 m. A bullet pierces A and then B. The hole in B is 15 cm below the hole on screen A. If the bullet is travelling horizontally at the time of hitting A, then the velocity of the bullet at A is : (Take g = 10 ms-2 )

a
1003ms−1
b
2003ms−1
c
3003ms−1
d
5003ms−1

detailed solution

Correct option is D

Range = 150 = ut andh=15100=12gt2or t2=2100×15g=301000or t=310∴u=150t=150×103=5003ms−1

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Assertion : When the velocity of projection of a body is made n times, its time of flight becomes n times.

Reason : Range of projectile does not depend on the initial velocity of a body.


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