First slide

Projection Under uniform Acceleration

Question

Two paper screens A and B are separated by 150 m. A bullet pierces A and B. The hole in B is 15 cm below the hole in A. If the bullet is travelling horizontally at the time of hitting A, then the velocity of the bullet at A is: (g: 10 ${ms}^{- 2}$ ).

Moderate

A

100 $\sqrt{3}$ ${ms}^{- 1}$
B

200 $\sqrt{3}$ ${ms}^{- 1}$
C

300 $\sqrt{3}$ ${ms}^{- 1}$
D

500 $\sqrt{3}$ ${ms}^{- 1}$

Solution

Range = 150 = ut and h = $\frac{15}{100} = \frac{1}{2} \times {gt}^{2}$
or $t^{2} = \frac{2 \times 15}{100 \times g} = \frac{30}{1000}$
$∴ t = \frac{\sqrt{3}}{10}$
$∴ u = \frac{150}{t} = \frac{150 \times 10}{\sqrt{3}} = 500 \sqrt{3} {ms}^{- 1}$

Get Instant Solutions

When in doubt download our app. Now available Google Play Store- Doubts App

Recieve an sms with download link

Doubts App

OR

SCAN ME

Doubts App

Doubts App