First slide

Projectile motion

Question

Two paper screens A and B are separated by 150 m. A bullet pierces A and B. The hole in B is 15 cm below the hole in A. If the bullet is travelling horizontally at the time of hitting A, then the velocity of the bullet at A is $(g = 10 {ms}^{- 2})$

Moderate

A

$100 \sqrt{3} {ms}^{- 1}$
B

$200 \sqrt{3} {ms}^{- 1}$
C

$300 \sqrt{3} {ms}^{- 1}$
D

$500 \sqrt{3} {ms}^{- 1}$

Solution

$\begin{array}{l} Range = 150 = u t and h = \frac{15}{100} = \frac{1}{2} \times g t^{2} \\ or t^{2} = \frac{2 \times 15}{100 \times g} = \frac{30}{1000} or t = \frac{\sqrt{3}}{10} \\ u = \frac{150}{t} = \frac{150 \times 10}{\sqrt{3}} = 500 \sqrt{3} {ms}^{- 1} \end{array}$

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