Two parallel glass plates are dipped partly in the liquid of density 'd' keeping them vertical. If the distance between the plates is 'x', surface tension for liquids is T and angle of contact is  θ, then rise of liquid between the plates due to capillary will be

Let the width of each plate is b and due to surface tension liquid will rise upto height h then upward force due to surface tension =  2Tbcos⁡θ   …(i)Weight of the liquid rises in between the plates =   Vdg=(bxh)dg  …(ii)Equating (i) and (ii) we get , 2Tcos⁡θ=bxhdg ∴h=2Tcos⁡θxdg