Two parallel glass plates are dipped partly in the liquid of density 'd' keeping them vertical. If the distance between the plates is 'x', surface tension for liquids is T and angle of contact is θ then rise of liquid between the plates due to capillary will be
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a
Tcosθxd
b
2Tcosθxdg
c
2Txdgcosθ
d
Tcosθxdg
answer is B.
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Detailed Solution
Let the width of each plate is b and due to surface tension, liquid will rise upto height h. Then upward force due to surface tension = 2Tb cosθ….(i)weight of the liquid that rises in between the plates=Vdg=(bxh)dg Equating (i) and (ii), we get 2Tcosθ=bxhdgh=2Tcosθxdg
Two parallel glass plates are dipped partly in the liquid of density 'd' keeping them vertical. If the distance between the plates is 'x', surface tension for liquids is T and angle of contact is θ then rise of liquid between the plates due to capillary will be