First slide

Resolving power of optical instruments

Question

Two parallel pillars are 11 km away from an observer. The minimum distance between the pillars so that they can be seen separately will be

Moderate

A

3.2 m
B

20.8 m
C

91.5 m
D

183 m

Solution

$As limit of resolution of eye is {(\frac{1}{60})}^{\circ}, the pillars will be seen distinctly if θ > {(\frac{1}{60})}^{\circ}$

${i.e.}_{는} \frac{d}{x} > (\frac{1}{60}) \times \frac{π}{180} \Rightarrow d > \frac{π \times x}{60 \times 180} \Rightarrow d > \frac{3 .14 \times 11 \times 10^{3}}{60 \times 180} \Rightarrow d > 3 .2 m$

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