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Q.

Two parallel plate capacitors of capacitance C and 2C are connected in parallel and charged to a potential difference V by a battery. The battery is then C disconnected and the space between the plates of capacitor C is completely filled with a material of dielectric constant K. The potential difference across the capacitors now becomes:

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a

VK+1

b

2VK+1

c

3VK+2

d

3VK+3

answer is C.

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Detailed Solution

Total original capacitance of system = C + 2C = 3Cif C is filled with delectric of K. dielectric constant K.Then C' = KCNow, capacitance of system C" = C' +2C = (K + 2) C∴ Pot. difference =QC′′=3CV(K+2)C=3VK+2.

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