Two parallel plate capacitors of capacitance C and $$2C$$ are connected in parallel and charged to a potential difference V by a battery. The battery is then C disconnected and the space between the plates of capacitor C is completely filled with a material of dielectric constant K. The potential difference across the capacitors now becomes:

Question

Infinity Learn · Accepted Answer

Total original capacitance of system $$=$$ C $$+$$ $$2C$$ $$=$$ $$3Cif$$ C is filled with delectric of K. dielectric constant K.Then C' $$=$$ KCNow, capacitance of system C" $$=$$ C' $$+2C$$ $$=$$ (K$$ $$+$$ $$2) C∴ Pot. difference $$=QC$$′′$$=3CV(K+2)C=3VK+2$$.

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