Questions
Two parallel plate capacitors of capacitances C and 2C are connected in parallel and charged to a potential difference V by a battery. The battery is then disconnected and the space between the plate of capacitor OF CAPACITY C is completely filled with a material of dielectric constant K. The potential difference across the capacitor now becomes
detailed solution
Correct option is A
The capacitors are connected in parallel. So, the resultant capacitance =C+2C=3C∴Total charge Q = 3 CVWhen the capacitor of capacity C is filled with dielectric, its capacitance becomes KC. The new resultant capacitance becomes C′=KC+2C=(K+2)C.As charge remains the same, Q = 3CV∴ QC′=3CV(K+2)C=3VK+2Talk to our academic expert!
Similar Questions
A parallel plate, air filled capacitor has capacitance C. When a dielectric material of dielectric constant 4 is filled so that half of the space between plates is occupied by it, then percentage increase in the capacitance is equal to
799 666 8865
support@infinitylearn.com
6th Floor, NCC Building, Durgamma Cheruvu Road, Vittal Rao Nagar, HITEC City, Hyderabad, Telangana 500081.
JEE Mock Tests
JEE study guide
JEE Revision Notes
JEE Important Questions
JEE Sample Papers
JEE Previous Year's Papers
NEET previous year’s papers
NEET important questions
NEET sample papers
NEET revision notes
NEET study guide
NEET mock tests