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Q.

Two parallel plate capacitors of capacitances C and 2C are connected in parallel and charged to a potential difference V by a battery. The battery is then disconnected and the space between the plate of capacitor OF CAPACITY C is completely filled with a material of dielectric constant K. The potential difference across the capacitor now becomes

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a

3VK+2

b

K+23V

c

VK+2

d

VK+3

answer is A.

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Detailed Solution

The capacitors are connected in parallel. So, the resultant capacitance =C+2C=3C∴Total charge Q = 3 CVWhen the capacitor of capacity C is filled with dielectric, its capacitance becomes KC. The new resultant capacitance becomes C′=KC+2C=(K+2)C.As charge remains the same, Q = 3CV∴ QC′=3CV(K+2)C=3VK+2

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