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Q.

Two parallel plates separated by a distance of 5 mm are kept at a potential difference of 50 V. A particle of mass 10-15 kg and charge 10-11 C enters in it with a velocity 107 m/s. The acceleration of the particle will be

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a

108 m/s2

b

5 x 105 m/s2

c

105 m/s2

d

2 x 103 m/s2

answer is A.

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Detailed Solution

a=qEm=qmVd=10-1110-15×505×10-3=108 m/sec2
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