First slide

Electrostatic potential

Question

Two parallel plates separated by a distance of 5 mm are kept at a potential difference of 50 V. A particle of mass 10^-15 kg and charge 10^-11 C enters in it with a velocity 10⁷ m/s. The acceleration of the particle will be

Moderate

A

10⁸ m/s²
B

5 x 10⁵ m/s²
C

10⁵ m/s²
D

2 x 10³ m/s²

Solution

$a = \frac{qE}{m} = \frac{q}{m} (\frac{V}{d}) = \frac{10^{- 11}}{10^{- 15}} \times \frac{50}{5 \times 10^{- 3}} = 10^{8} m / \sec^{2}$

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