Two particle are projected from the same point with same speed in same vertical plane but at different angles of projection such that they produce the same range. If the ratio of their times of flight is 3:1, their angles of projection are

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37o and 53o

50o and 40o

30o and 60o

35o and 55o

answer is C.

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Detailed Solution

It angle of projection of one particle is α, that of the other particle must be 90o-α∴ Tα=2usinαg and Tβ=2usin90o−αg=2ucosαgNow TαTβ=3⇒tanα=3⇒α=60o

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