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Q.

Two particles are executing SHM in a straight line with same amplitude A and time period T. At time t = 0, one particle is at displacement x1 = +A and the other at x2 = -A/ 2 and they are approaching towards each other. After what time they cross each other?

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a

T3

b

T4

c

5T6

d

T6

answer is D.

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Detailed Solution

Total time =2t=T4+T12

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Two particles are executing SHM in a straight line with same amplitude A and time period T. At time t = 0, one particle is at displacement x1 = +A and the other at x2 = -A/ 2 and they are approaching towards each other. After what time they cross each other?