Two particles are executing simple harmonic motion. At an instant of time t, their displacements ay1= A cos (ωt) and y2 = A sin (ωt) Then, the phase difference between y1 and y2 is
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a
120°
b
90°
c
180°
d
zero
answer is B.
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Detailed Solution
y1=A cos ωt=A sin ωt+π2y2=A sin ωt∴ Δϕ=ωt+π2-ωt=π2=90°