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Q.

Two particles are executing simple harmonic motion. At an instant of time t, their displacements ay1= A cos (ωt) and y2 = A sin (ωt) Then, the phase difference between y1 and y2 is

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a

120°

b

90°

c

180°

d

zero

answer is B.

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Detailed Solution

y1=A cos ωt=A sin ωt+π2y2=A sin ωt∴   Δϕ=ωt+π2-ωt=π2=90°
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