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Two particles are executing simple harmonic motion at an instant of time 't' their displacements are y1=acos(wt)  and y2=asin(wt) . Then the phase difference between y1  and  y2 is

a
120∘
b
90∘
c
180∘
d
Zero

detailed solution

Correct option is B

displacement of 1st particle=y1=acos(wt)=asinwt+π/2 displacement of 2nd particle=y2=asin(wt) phase difference between above two equations =Δφ=wt+π/2-wt=π/2=900 Δφ=90∘

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