Two particles are executing simple harmonic motion at an instant of time 't' their displacements are y1=acos(wt) and y2=asin(wt) . Then the phase difference between y1 and y2 is
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a
120∘
b
90∘
c
180∘
d
Zero
answer is B.
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Detailed Solution
y1=acos(wt) =asinwt+π/2, here phase angle φ1=wt+π/2 y2=asin(wt), here phase angle φ2=wt phase difference =Δφ=φ1-φ2 Δφ=wt+π/2-wt=π2 radians Δφ=90∘ (in degrees)