Two particles are oscillating along two close parallel straight lines side by side, with the same frequency and amplitudes. They pass each other, moving in opposite directions when their displacement is half of the amplitude. The mean positions of the two particles lie on a straight line perpendicular to the paths of the two particles. The phase difference is

Question

Infinity Learn · Accepted Answer

Equation of SHM is given by x $$=$$ A $$sin$$ $$($$ω$$t+$$δ$$)($$ωt $$=$$ δ$$)$$ is called phase.when x $$=$$ $$A2$$, then   $$sin$$$$($$ω$$t+$$δ$$)$$ $$=$$ $$12$$  ⇒ ω$$t+$$δ $$=$$ π$$6or$$ φ$$1$$ $$=$$ π$$6For$$ second particle, ϕ$$2$$ $$=$$ π$$-$$π$$6$$ $$=$$ $$5$$$$π$$$$6$$    ∴    ϕ$$2-$$ϕ$$1$$        $$=$$ $$4$$$$π$$$$6=$$ $$2$$$$π$$$$3$$

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