Two particles are projected in air with speed u at angles θ1 and θ2(both acute) to the horizontal, respectively. If the height reached by the first particle is greater than that of the second, then which one of the following is correct?
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a
θ1 > θ2
b
θ1 = θ2
c
T1 < T2
d
T1 = T2where T1 and T2 are the time of flight.
answer is A.
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Detailed Solution
Height H = u2sin2θ2gFor the same speedH ∝ sin2 θ∵ H1 > H2 (Given)∴ sin2θ1 > sin2θ2or θ1 > θ2----------(i)Time of flight, T = 2u sinθgFor the same speedT ∝sin θθ1 > θ2 (From (i))∴ sin θ1 > sin θ2 ⇒ T1 > T2