Two particles are projected from the same point with same speed u at angles of projection α and β fromhorizontal. The maximum heights attained by them are h1 and h2 respectively, R is the range for both. Ift1 and t2 are their times of flight respectively, then which amongst the option{s) is/are incorrect?
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a
α+β=π2
b
R=4h1h2
c
tanα=t1t2=h1h2
d
tanα=h1h2
answer is D.
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Detailed Solution
Range becomes equal at complimentary angle. Hence,β=90°-α or α+β=90°=π/2(b) h1=u2sin2α2g ⇒ h2=u2cos2α2g As, β=90°-α ∴4h1h2=2u2sinαcosαg=u2sin2αg=R(c) t1t2=(2usinα/g)(2ucosα/g)=tanα(d) h1h2=tanα