Two particles are projected from the same point with the same speed at different angles θ1 and θ2 to the horizontal. They have the same range. Their times of flight are t1 and t2, respectively. Then choose the correct option(s).

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θ1=90−θ2

t1t2=tan⁡θ2

t1sin⁡θ1=t2sin⁡θ2

t1t2=tanθ1

answer is A.

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Detailed Solution

R=u2sin⁡2θg is same for angles θ and 90∘−θ. t1=2usin⁡θ1g=2usin⁡90∘−θ2gt2=2usinθ2g=2usin90∘−θ1g

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