Two particles are projected simultaneously one with velocity V up on a smooth inclined plane of inclination $$300$$ to the horizontal and the other with a velocity $$2V3$$ at an angle $$600$$. The particles will be relatively at rest at the end of time is

Question

Two particles are projected simultaneously one with velocity V up on a smooth inclined plane of inclination  $$300$$ to the horizontal and the other with a velocity $$2V3$$  at an angle $$600$$. The particles will be relatively at rest at the end of time is

Infinity Learn · Accepted Answer

The particles will be relatively at rest if vertical component of velocity, perpendicular to inclined $$plane=0$$ because first particle, component of velocity, perpendicular to inclined $$plane=0$$ $$vy=uy+ayt=0$$ $$vy=finial$$ vertical component of velocity;$$uy=initial$$ vertical component of velocity;$$ay=acceleration$$ due to $$gravity=-gcos$$θ $$2V3sin300$$−$$gcos300t=0$$ $$t=2v3sin300gcos300$$ $$t=2V3g$$×$$13=2V3gs$$

Two particles are projected simultaneously one with velocity V up on a smooth inclined plane of inclination $3 0^{0}$ to the horizontal and the other with a velocity $\frac{2 V}{\sqrt{3}}$ at an angle $6 0^{0}$ . The particles will be relatively at rest at the end of time is

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Two particles are projected simultaneously one with velocity V up on a smooth inclined plane of inclination 300 to the horizontal and the other with a velocity 2V3 at an angle 600. The particles will be relatively at rest at the end of time is

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Two particles are projected simultaneously one with velocity V up on a smooth inclined plane of inclination $3 0^{0}$ to the horizontal and the other with a velocity $\frac{2 V}{\sqrt{3}}$ at an angle $6 0^{0}$ . The particles will be relatively at rest at the end of time is