First slide

Projection Under uniform Acceleration

Question

Two particles are projected with same initial velocity one makes an angle $θ$ with horizontal while other makes an angle $θ$ with vertical. If their common range is R, then product of their time of flight is directly proportional to :

Moderate

A

R
B

R²
C

$\frac{1}{R}$
D

R°

Solution

$t_{1} = \frac{2 usinθ}{g} and t_{2} = \frac{2 ucosθ}{g}$
$\Rightarrow t_{1} t_{2} = \frac{4 u^{2} sinθcosθ}{g^{2}}$
$= \frac{2 R}{g} \propto R$

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