Two particles are projected with same initial velocity one makes an angle θ with horizontal while other makes an angle θ with vertical. If their common range is R, then product of their time of flight is directly proportional to :
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a
R
b
R2
c
1R
d
R°
answer is A.
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Detailed Solution
t1=2usinθg and t2=2ucosθg⇒t1t2=4u2sinθcosθg2=2Rg∝R