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Q.

Two particles are separated by a distance d. When the positions of the two particles are interchanged, the shift in the position of their centre of mass is d/3. If the mass of lighter particle is m, the mass of heavier particle is

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a

3m2

b

4m3

c

2m

d

3m

answer is C.

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Detailed Solution

let m1 be smaller mass, thenx1=m2dm1+m2 and x2=m1dm1+m2x1-x2=m2-m1dm1+m2=d3⇒m2=2m1=2m

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