Questions
Two particles are shown in the figure. At t=0, a constant force F=6 N starts acting on the 3 kg man.
Find the velocity of the centre of mass of these particles at t=5 s
detailed solution
Correct option is C
Method 1: Acceleration of 3 kg: a2=63=2m/s2 Velocity of 3kg at t=5s:v2=u2+a2t=0+2×5=10m/svCM(t=5s)=2×0+3×102+3=6m/sMethod 2:aCM=Fm1+m2=62+3=1.2m/s2vCM=uCM+aCMt=0+1.2×5=6m/sTalk to our academic expert!
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Shown in the figure is a system of three particles of mass 1 kg, 2 kg and 4 kg connected by two springs. The acceleration of A, B and C at any instant are 1 ms-2, 2 ms-2 and 1/2 ms-2 respectively directed as shown in the figure external force acting on the system is:
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