Two particles A and B are projected simultaneously from a point situated on a horizontal place. The particle A is projected vertically up with a velocity vA while the particle B is projected up at an angle of 300 with horizontal with a velocity vB. After 5 s the particles were observed moving mutually perpendicular to each other. The velocity of projection of the particle vA and vB respectively are:
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a
50 ms-1, 100 m/s
b
100 ms-1, 50 m/s
c
vA can have any value greater than a certain value, 100 ms-1
d
none of these
answer is C.
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Detailed Solution
Velocity of A is always in vertical direction. Time of ascent = vBsin300g = 5 s⇒vB=100 m/sAt 5 s, velocity of B is perpendicular to that of A. It means velocity of B is horizontal or B is at highest point.Now velocity of A can have any value provided its time of flight is more than 5 s.2VAg⩾5For that vA ≥25 m/s