Two particles ,$$4$$ and B are shot from the same height at t $$=$$ $$0$$ in opposite directions with horizontal velocities $$3$$ $$m/s$$ and $$4$$ $$m/s$$ respectively. If they are subjected to the same vertical acceleration due to $$gravity(g$$ $$=$$ $$9.8m/s2)$$'the distance between them when their velocity vectors become mutually perpendicular, is :

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Infinity Learn · Accepted Answer

v→$$A=4i$$−$$gtj^$$ and v→$$A=$$−$$3i^$$−$$gtj^If$$ v→A⊥v→B then, v→A.v→$$B=0-12+$$ $$g2$$ $$t2$$ $$=$$ $$0t=12gSeparation$$ between particles $$=$$ (4$$ $$+$$ $$3) (t) $$=$$ $$7129.8$$ $$=$$ $$2.474$$ m

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