Two particles A and B (B is right of A) having charges 8×10−6 C and −2×10−6 C, respectively, are held fixed with separation of 20 cm. Where should a third charged particle be placed so that it does not experience a net electric force?

see full answer

High-Paying Jobs That Even AI Can’t Replace — Through JEE/NEET

🎯 Hear from the experts why preparing for JEE/NEET today sets you up for future-proof, high-income careers tomorrow.

An Intiative by Sri Chaitanya

5 cm right of B

5 cm left of A

20 cm left of A

20 cm right of B

answer is D.

(Unlock A.I Detailed Solution for FREE)

Detailed Solution

Let the third charge Q be placed at a distance x to the right of B. ThenkQ×8×10−6(20+x)2=kQ(2×106)x2or x = 20 cm

Watch 3-min video & get full concept clarity