Two particles A and B (B is right of A) having charges 8×10−6 C and −2×10−6 C, respectively, are held fixed with separation of 20 cm. Where should a third charged particle be placed so that it does not experience a net electric force?

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5 cm right of B

5 cm left of A

20 cm left of A

20 cm right of B

answer is D.

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Detailed Solution

Let the third charge Q be placed at a distance x to the right of B. ThenkQ×8×10−6(20+x)2=kQ(2×106)x2or x = 20 cm

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