Two particles A and B, each of mass m, are kept stationary by applying a horizontal force F = mg on particle B as shown in figure. Then

From figure, T2cosβ=mg, T2sinβ=mgTherefore T2= 2mg   and tan β = 1  Also ,T1sin⁡α=T2 cos β =2mg ×12  ⇒T1sin⁡α=mg and T1 cos α =mg +T2 cos β =mg+mg = 2mgtan⁡α=12 ⇒ cos⁡α=25T125=2mg ⇒ T1=mg5T1T2=52⇒2T1=5T2