Two particles A and B , each of mass m, are kept stationary by applying a horizontal force F = mg on particle B as shown in the figure. Then
2tanβ=tanα
2T1=5T2
T12=T25
None of these
From the figure T2cosβ=mg, T2sinβ=mg
T1sinα=T2sinβ=mgT1cosα=mg+T2cosβ=2mg⇒cosαsinα=2mgmgtanα=12⇒cosα=25T125=2mg ⇒ T1=mg5T1T2=52⇒2T1=5T2