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Two particles A and B , each of mass m, are kept stationary by applying a horizontal force F = mg on particle B as shown in the figure. Then
detailed solution
Correct option is C
From the figure T2cosβ=mg, T2sinβ=mgT1sinα=T2sinβ=mgT1cosα=mg+T2cosβ=2mg⇒cosαsinα=2mgmgtanα=12⇒cosα=25T125=2mg ⇒ T1=mg5T1T2=52⇒2T1=5T2Talk to our academic expert!
Similar Questions
Natural length of the spring is 40 cm and its spring constant is 4000 N m-1. A mass of 20 kg is hung from it. The extension produced in the spring is (Given g = 9.8 m s-2)
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