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Questions  

Two particles A and B of equal masses are suspended from two mass less spring of spring constants K1 and K2 respectively. If the maximum velocities, during oscillations are equal. The ratio of amplitudes of 'A' and 'B'.

a
K1K2
b
K1K2
c
K2K1
d
K2K1

detailed solution

Correct option is C

maximum velocity is       vmax=Aω, here A=amplitude, ω=angular frequency,T=time period, m=mass of oscillator,k=force constantω=2πT Vmax=A2π2πmk Vmax=Akm Hence consider ratio of maximum velocity at A and B vmax1vmax2=A1A2K1/mK2/m  given vmax1=vmax2 A1A2=K2K1

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