Questions
Two particles A and B of equal masses are suspended from two mass less spring of spring constants and respectively. If the maximum velocities, during oscillations are equal. The ratio of amplitudes of 'A' and 'B'.
detailed solution
Correct option is C
maximum velocity is vmax=Aω, here A=amplitude, ω=angular frequency,T=time period, m=mass of oscillator,k=force constantω=2πT Vmax=A2π2πmk Vmax=Akm Hence consider ratio of maximum velocity at A and B vmax1vmax2=A1A2K1/mK2/m given vmax1=vmax2 A1A2=K2K1Talk to our academic expert!
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