Questions
Two particles A and B of masses m and 2m are at a separation d. PQ is a line perpendicular to the line AB. Then minimum possible moment of inertia about PQ is
detailed solution
Correct option is D
IPQ will be minimum when line PQ passes through the centre of mass of the system∴ AP = 2m×d3m = 2d3 and BP = d−2d3 = d3 ∴IPQ min=m2d32+2md32a =23md2Talk to our academic expert!
Similar Questions
Three point masses, each of m, are placed at the corners of an equilateral triangle of side l. Then the moment of inertia of this system about an axis along one side of the triangle is
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