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Questions  

Two particles A and B of masses mA and. mB respectively and having the same charge are moving in a plane. A uniform magnetic field exists perpendicular to this plane. The speeds of the particles are vA and vB respectively and trajectories are as shown in fig

Then

a
mAVA
b
mAVA>mBVB
c
mA
d
mA=mB and vA=vB

detailed solution

Correct option is B

We know that m v = BqrFrom given figure, rA > rB∴ mAvA>mBvB

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