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Q.

Two particles A and B of masses mA and. mB respectively and having the same charge are moving in a plane. A uniform magnetic field exists perpendicular to this plane. The speeds of the particles are vA and vB respectively and trajectories are as shown in figThen

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a

mAVA

b

mAVA>mBVB

c

mA

d

mA=mB and vA=vB

answer is B.

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Detailed Solution

We know that m v = BqrFrom given figure, rA > rB∴ mAvA>mBvB
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