Two particles each having charge of 5μC are placed at a separation of 1m. what would be the work done by external force in pulling them apart slowly by 2m, so that new separation becomes 3m?

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answer is 3.

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Detailed Solution

From work energy theorem, ΔK=Wext+Wint=Wext−Wele0=Wext−Uf−UiWext=q1q24πε01r2−1r1=5×10−62×9×10913−1=−0.15J

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