Questions
Two particles each of mass m are placed at points A and C such that AB =BC =L as shown in fig.
The gravitational force on a third particle placed at D at a distance I metre on the perpendicular bisector of the line AC, is
detailed solution
Correct option is B
Here F=Gm2(2L)2=Gm22L2The resultant force on mass m placed at point D is F' = 2 F cos 45o long DB=2Gm22L2×12=Gm22L2 along DBTalk to our academic expert!
Similar Questions
Four particles of equal mass M move along a circle of radius .R under the action of their mutual gravitational attraction [Fig.]. The speed of each particle is
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