Two particles each of mass m and charge q are attached to two ends of a light rod of length 2l. The rod is rotated at a constant angular speed about a perpendicular axis passing through its centre. The ratio of the magnitudes of the magnetic moment of the system to its angular momentum will be
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a
q/m
b
q/2m
c
2q/m
d
q/πm
answer is B.
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Detailed Solution
The magnetic moment M is given byM=iA=2qω2ππl2…The angular momentum I is given byL=Iω=2ml2ω∴ML=q2m