First slide

Magnetic Dipole moment

Question

Two particles each of mass m and charge q are attached to two ends of a light rod of length 2l. The rod is rotated at a constant angular speed about a perpendicular axis passing through its centre. The ratio of the magnitudes of the magnetic moment of the system to its angular momentum will be

Moderate

A

q/m
B

q/2m
C

2q/m
D

q/ $π$ m

Solution

The magnetic moment M is given by
$M = iA = (\frac{2 qω}{2 π}) ({πl}^{2}) \dots$
The angular momentum I is given by
$\begin{array}{l} L = Iω = 2 {ml}^{2} ω \\ ∴ \frac{M}{L} = \frac{q}{2 m} \end{array}$

Get Instant Solutions

When in doubt download our app. Now available Google Play Store- Doubts App

Recieve an sms with download link

Doubts App

OR

SCAN ME

Doubts App

Doubts App