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Two particles of equal mass go around a circle of radius R under the action of their mutual gravitational attraction. The speed v of each particle is 

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a
12R1Gm
b
Gm2R
c
12GmR
d
4GmR

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detailed solution

Correct option is C

Gmm(2R)2=mv2R∴ v2=Gm4R  or  v=12GmR


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