Q.

Two particles of equal mass go around a circle of radius R under the action of their mutual gravitational attraction. The speed v of each particle is

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a

12R1Gm

b

Gm2R

c

12GmR

d

4GmR

answer is C.

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Detailed Solution

Gmm(2R)2=mv2R∴ v2=Gm4R  or  v=12GmR
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Two particles of equal mass go around a circle of radius R under the action of their mutual gravitational attraction. The speed v of each particle is