Questions
Two particles of equal mass go around a circle of radius R under the action of their mutual gravitational attraction. The speed of each particle is
a
v=12R1Gm
b
v=Gm2R
c
v=12GmR
d
v=4GmR
detailed solution
Correct option is C
FG=Gm24R2⇒mv2R=Gm24R2∴ v=12GmRTalk to our academic expert!
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