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Questions  

Two particles of equal mass go round a circle of radius R under the action of their mutual gravitational attraction. The speed of each particle is

a
v=12R1Gm
b
v=Gm2R
c
v=12GmR
d
v=4GmR

detailed solution

Correct option is C

Centripetal force provided by the gravitational force of attraction between two particlesi.e. mv2R=Gm×m(2R)2 ⇒v=12GmR

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