Two particles of equal mass have velocities v1→=4i^ and v2→=4j^ m/sec. First particle has an acceleration a1→=(5i^+5j^) ms-2 while the acceleration of the other particle is zero. The centre of mass of the two particles moves in a path of
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a
Straight line
b
Parabola
c
Circle
d
Ellipse
answer is A.
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Detailed Solution
At any time 't',co-ordinates of CM = (xcm, ycm) xcm=m(4t+12.5.t2)m+m=2t+5t24similarly ycm=m(0+12.5.t2)+m(4t)m+m=5t24+2tHere xcm=ycm for all 't'Hence, the path of CM is straight line passing through origin making angle 450