Two particles of equal mass have velocities $$v1$$→$$=4i^$$ and $$v2$$→$$=4j^$$ $$m/$$$$sec$$. First particle has an acceleration $$a1$$→$$=(5i^+5j^)$$ $$ms-2$$ while the acceleration of the other particle is zero. The centre of mass of the two particles moves in a path of

Question

Two particles of equal mass have velocities $$v1$$→$$=4i^$$ and $$v2$$→$$=4j^$$ $$m/$$$$sec$$. First particle has an acceleration $$a1$$→$$=(5i^+5j^)$$ $$ms-2$$ while the acceleration of the other particle is zero. The centre of mass of the two particles moves in a path of

Infinity Learn · Accepted Answer

At any time 't',$$co-ordinates$$ of CM $$=$$ (xcm$$, $$ycm) $$xcm=m(4t+12.5$$.$$t2)m+m=2t+5t24similarly$$ $$ycm=m(0+12.5$$.$$t2)+m(4t)m+m=5t24+2tHere$$ $$xcm=ycm$$ for all 't'Hence, the path of CM is straight line passing through origin making angle $$450$$

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Two particles of equal mass have velocities v1→=4i^ and v2→=4j^ m/sec. First particle has an acceleration a1→=(5i^+5j^) ms-2 while the acceleration of the other particle is zero. The centre of mass of the two particles moves in a path of

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