Two particles of equal mass m go round a circle of radius R under the action of their mutual gravitational attraction. The speed of each particle is

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v = GmR

v = Gm2R

v = 12 GmR

v = 4GmR

answer is C.

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Detailed Solution

As gravitational force provides the centripetal force to the satellite to revolve around the earth,G.m.m4R2 = mv2(R) ⇒ v = 12GmR

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