Two particles of equal masses have velocity v→1 = 2i^ m/s and v1→ = 2j^ m/s. The first particle has an acceleration a1→ = (3i^+3j^) m/s2 while the acceleration of the other particle is zero. The centre of mass of the two particles moves in a:
see full answer
Your Exam Success, Personally Taken Care Of
1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.
An Intiative by Sri Chaitanya
a
circle
b
parabola
c
straight line
d
ellipse
answer is C.
(Unlock A.I Detailed Solution for FREE)
Best Courses for You
JEE
NEET
Foundation JEE
Foundation NEET
CBSE
Detailed Solution
vcm→ = m2i^+m2j^m+m = i^+j^ m/sacm→ = m(3i^+3j^)+m×0m+m = 32i^+32j^Since acceleration and velocity are in same direction, so path should be straight line.