First slide

Location of centre on mass for multiple point masses

Question

Two particles of masses 4 kg and 6 kg are at rest separated by 20 m. If they move towards each other under mutual force of attraction, the position of the point where they meet is

Easy

A

12m from 4kg body
B

12m from 6kg body
C

8m from 4kg body
D

10m from 4kg body

Solution

m₁ = 4kg, m₂ = 6kg, d = 20m
distance from m₁ is
$\large {x_1} = \frac{{{m_2}d}}{{{m_1} + {m_2}}} = \frac{{6 \times 20}}{{4 + 6}} = 12m$

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